![SOLVED: A simply supported aluminum beam of a square cross-section with a span of 1.8 m carries a uniformly distributed load of 2.5 kN/m. If the maximum bending stress is 60 N/mm^2, SOLVED: A simply supported aluminum beam of a square cross-section with a span of 1.8 m carries a uniformly distributed load of 2.5 kN/m. If the maximum bending stress is 60 N/mm^2,](https://cdn.numerade.com/ask_images/5b1d4dafd04d46619a4474959a5bfe2a.jpg)
SOLVED: A simply supported aluminum beam of a square cross-section with a span of 1.8 m carries a uniformly distributed load of 2.5 kN/m. If the maximum bending stress is 60 N/mm^2,
![SOLVED: The deflection of a propped cantilever beam under uniformly distributed load, w, as shown above can be computed with the following formula: y(x) = √(w * L^4 - 3 - 48E) SOLVED: The deflection of a propped cantilever beam under uniformly distributed load, w, as shown above can be computed with the following formula: y(x) = √(w * L^4 - 3 - 48E)](https://cdn.numerade.com/ask_images/dcf5e6b86ebb40e390516e623ea2f2f6.jpg)
SOLVED: The deflection of a propped cantilever beam under uniformly distributed load, w, as shown above can be computed with the following formula: y(x) = √(w * L^4 - 3 - 48E)
![SOLVED: For the beam shown below, Wo = 987 N/mm and L = 1,954 mm. Wo L/4 D E Find: (b) Bending moment at E in kN.m SOLVED: For the beam shown below, Wo = 987 N/mm and L = 1,954 mm. Wo L/4 D E Find: (b) Bending moment at E in kN.m](https://cdn.numerade.com/ask_images/a8da1f6f93f04197bf11ea0df17c6016.jpg)
SOLVED: For the beam shown below, Wo = 987 N/mm and L = 1,954 mm. Wo L/4 D E Find: (b) Bending moment at E in kN.m
![Deflection of flexible link SOLUTION L=500 mm E=2×10 5 N/mm 2 w=80 mm... | Download Scientific Diagram Deflection of flexible link SOLUTION L=500 mm E=2×10 5 N/mm 2 w=80 mm... | Download Scientific Diagram](https://www.researchgate.net/publication/281405197/figure/fig1/AS:391454477307909@1470341428545/Deflection-of-flexible-link-SOLUTION-L500-mm-E210-5-N-mm-2-w80-mm-t1-mm-W20-KN-m.png)